CBSE Class 10 Science Sample Paper Term 2 

CBSE Class 10 Science Sample Paper Term 2: CBSE has scheduled Science Term 2 Exam for 10th May 2022 (Tuesday) and students must buckle up their preparation by revising the complete syllabus, mock tests, and practice papers. In all these, the students must not skip the official CBSE Class 10 Term 2 Science Paper in order to understand the pattern and plan a strategy to solve the questions in the given time duration. For providing a helping hand to the students, CBSE has released the Class 10 Science Sample Paper Term-2 PDF set in the official format along with all subjects' sample paper for class 10th term 2. The sample papers have been uploaded on the CBSE Academic official website www.cbseacademic.nic.in and we have also provided the direct links in this article. Download Class 10th Science Sample Paper 2022 Term 2 and prepare according to the latest pattern. 

Science Sample Paper Class 10 Term 2

As CBSE Term 2 exam is heading and students must have been preparing for the exam with the new exam pattern as announced by CBSE for the academic year 2021-22. The CBSE Class 10 Science Term 2 Exam will be of descriptive nature for which the time allotted is 2 hours for 15 questions. The paper will be divided into 3 sections-

1. Section–A has 7 questions of 2 marks each

2. Section–B has 6 questions of 3 marks each

3. Section–C has 2 case-based questions of 4 marks each

CBSE Class 10 Science Term 2 Answer Key 2022- Click Here

Class 10 Science Sample Paper Term 2 PDF

The students who are studying for CBSE Class 10 Science Term 2 Examination can download the official Class 10 Science Sample Paper Term 2 PDF from the below link and practice the questions as per the pattern released by CBSE. Also practice with these Class 10 Science Term 2 Sample Papers prepared by our esteemed faculty. 

Class 10 Term 2 Science Sample Paper with Solutions
Sample PaperSolution
Class 10 Science Term 2 Sample Paper- 1 [Official]Solution Link
Class 10 Science Term 2 Sample Paper - 2Solution Link
Class 10 Science Term 2 Sample Paper - 3Solution Link
Class 10 Science Term 2 Sample Paper - 4Solution Link
Class 10 Science Term 2 Sample Paper - 5Solution Link
Class 10 Science Term 2 Sample Paper - 6 [NEW]Solution Link

Science Class 10 Term 2 Answer Key & Solutions

Sample Paper Class 10 Science with Answers

The solutions to the CBSE Class 10 Science Sample Paper as set by CBSE based on CBSE Class 10 Science Term 2 Syllabus has been provided below along with the sample paper as released by CBSE. Practice with the sample questions from the below section and prepare yourself for the Term 2 Exam in an efficient manner. 

Question 1- The table shows the electronic structures of four elements.

ElementElectronic Structure
P2,6
Q2,8,1
R2,8,7
S2,8,8

a. Identify which element(s) will form covalent bonds with carbon. 

Answer- P and R

b. “Carbon reacts with an element in the above table to form several compounds.” Give suitable reason.

Answer- Carbon has a valency four or Tetravalency & Catenation

Question 2- The diagram below shows part of the periodic table. 

CBSE Class 10 Science Term 2 Sample Paper & Solutions_90.1

a) Which elements would react together to form covalent compounds? 

Answer- Y and Z

b) Between the two elements W and Z, which will have a bigger atomic radius? Why?

Answer- W is bigger

Question 3- Answer the following 

a) Trace the path a male gamete takes to fertilise a female gamete after being released from the penis. 

Answer- The male gamete (sperm) travels in the female reproductive tract after being released. The path which it takes to fertilise the female gamete (egg) is the vagina, uterus, fallopian tube resulting in a zygote; Alternatively, accept the labelled figure of the human female reproductive system indicating the passage of sperm from the vagina to uterus and then to the fallopian tube for fertilisation resulting in a zygote

b. State the number of sets of chromosomes present in a zygote.

Answer- Zygote has 2 sets of chromosomes/ alternatively accept 2n. No marks to be assigned for n or 3n.

Question 4- Rajesh observed a patch of greenish-black powdery mass on a stale piece of bread. 

a. Name the organism responsible for this and its specific mode of asexual reproduction. 

Answer- The greenish-black powdery mass on a stale piece of bread is due to bread mould Rhizopus which reproduces by spore formation.

b. Name its vegetative and reproductive parts.

Answer- Hyphae or thread-like structures are the vegetative part and tiny blob-like structures or sporangia are the reproductive parts.

Question 5- Mustard was growing in two fields- A and B. While Field A produced brown coloured seeds, field B produced yellow coloured seeds. It was observed that in field A, the offspring showed only the parental trait for consecutive generations, whereas in field B, the majority of the offspring showed a variation in the progeny. What are the probable reasons for these? 

Answer- In the field A, the reason for the parental trait in consecutive generations of the offspring is self-pollination. 
In the field B, variation is seen to occur because of the recombination of genes as cross-pollination is taking place.

OR 

In an asexually reproducing species, if a trait X exists in 5% of a population and trait Y exists in 70% of the same population, which of the two traits is likely to have arisen earlier? Give reason.

Answer- Trait Y which exists in 70% (larger fraction) of the population, is likely to have arisen earlier because in asexual reproduction, identical copies of DNA are produced and variations do not occur. 
New traits come in the population due to sudden mutation and then are inherited. 70% of the population with trait Y is likely to have been replicating that trait for a longer period than 5 % of the population with trait X. 

Question 6- A simple motor is made in a school laboratory. A coil of wire is mounted on an axle between the poles of a horseshoe magnet, as illustrated.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_100.1

In the example above, coil ABCD is horizontal and the battery is connected as shown. 

a) For this position, state the direction of the force on the arm AB. 

Answer- Downwards

b) Why does the current in the arm BC not contribute to the turning force on the coil?

Answer- Because BC is in the same direction as the direction of field lines. Force is minimum when the direction of current in the conductor is the same as that of the magnetic field. BC will not contribute as the force on this part of the coil will be cancelled by the force on DA.

OR

A circuit contains a battery, a variable resistor and a solenoid. The figure below shows the magnetic field pattern produced by the current in the solenoid.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_110.1

a) State how the magnetic field pattern indicates regions where the magnetic field is stronger. 

Answer- Relative closeness of field lines indicates the strength of the magnetic field. Since field lines are crowded around the ends of the solenoid, hence these are the regions of strongest magnetism.

b) What happens to the magnetic field when the current in the circuit is reversed?

Answer- The direction of the field will also be reversed.

Question 7- DDT was sprayed in a lake to regulate the breeding of mosquitoes. How would it affect the trophic levels in the following food chain associated with a lake? Justify your answer.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_120.1

Answer- 1. DDT being a non-biodegradable pesticide will enter the food chain from the first trophic level i.e Plankton. 

2. Non – biodegradable pesticides accumulate progressively at each trophic level. This phenomenon is known as biological magnification. (1mark)

3. HAWK will have the highest level of pesticide. 

OR 

In the following food chain, vertical arrows indicate the energy lost to the environment and horizontal arrows indicate energy transferred to the next trophic level. Which one of the three vertical arrows (A, C and E) and which one of the two horizontal arrows (B and D) will represent more energy transfer? Give a reason for your answer.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_130.1

Answer- A will represent more energy transfer as compared to C and E. B will represent more energy transfer as compared to D.
When green plants are eaten by primary consumers, a great deal of energy is lost as heat to the environment, some amount goes into digestion and in doing work and the rest goes towards growth and reproduction. An average of 10% of the food eaten is made available for the next level of consumers. This loss of energy takes place at every trophic level.

Alternatively, accept - In accordance with the 10% law of transfer of energy in a food chain only 10% of energy available at one trophic level is transferred to the next trophic level.

Question 8- Choose an element from period 3 of the modern periodic table that matches the description given below in each instance. Give reason for your choice. 

a) It has a similar structure to diamond. 

Answer- Silicon 

b) It has the same valency as Lithium. 

Answer- Sodium

c) It has variable valency and is a member of the Oxygen family (group 16).

Answer- Sulphur

Question 9- 

a) How many isomers are possible for the compound with the molecular formula C4H8? Draw the electron dot structure of branched chain isomer. 

Answer- Four 

CBSE Class 10 Science Term 2 Sample Paper & Solutions_140.1

b) How will you prove that C4H8 and C5H10 are homologues?

Answer- C4H8 and C5H10 are homologues as they differ in

  1. “- CH2-”
  2. differ in 14u molecular mass
  3. Same functional group
  4. Same general formula

OR 

A carbon compound ‘A’ having melting point 156K and boiling point 351K, with molecular formula C2H6O is soluble in water in all proportions. 

a) Identify ‘A’ and draw its electron dot structure. 

Answer- Ethanol; C2H5OH

CBSE Class 10 Science Term 2 Sample Paper & Solutions_150.1

b) Give the molecular formulae of any two homologues of ‘A’.

Answer- CH3OH and C3H7OH are homologues of ethanol or CH4O and C₃H₈O.

Question 10- Two pea plants - one with round yellow seeds (RRYY) and another with wrinkled green (rryy) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are self-pollinated, which new combination of characters is expected in F2 progeny? How many seeds with these new combinations of characters will be produced when a total 160 seeds are produced in F2 generation? Explain with reason.

Answer- Round green: 30 
Wrinkled yellow: 30 
New combinations are produced because of the independent inheritance of seed shape and seed colour traits. 

Question 11- 

a) It would cost a man Rs. 3.50 to buy 1.0 kW h of electrical energy from the Main Electricity Board. His generator has a maximum power of 2.0 kW. The generator produces energy at this maximum power for 3 hours. Calculate how much it would cost to buy the same amount of energy from the Main Electricity Board.

Answer- E = P X T
SO, E = 3X2 = 6 kWh
Cost of buying electricity from the main electricity board = 6 x 3.50 = Rs. 21.0

b) A student boils water in an electric kettle for 20 minutes. Using the same mains supply he wants to reduce the boiling time of water. To do so should he increase or decrease the length of the heating element? Justify your answer.

Answer- To reduce the boiling time using the same mains supply, the rate of heat production should be large. We know that P= V^2 /R. Since V is constant, R should be decreased. Since R is directly proportional to l so length should be decreased

Question 12- In the below circuit, if the current reading in the ammeter A is 2A, what would be the value of R1? 

CBSE Class 10 Science Term 2 Sample Paper & Solutions_160.1

Answer- 5 ohm, 10 ohm and R1 are in series

1/Rp = 1/5+1/10+1/R1

1/Rp = (2+1)/10 + 1/ R1

          = 3/10 +1/ R1

1/Rp = (3 R1 +10)/10 R1

Rp= 10 R1 / (3 R1 +10)

Now, 6 ohm, 6 ohm and Rp are in series

Thus, Req = 12 + 10 R1 / (3 R1 +10) ------------------ (1) 

V = I Req

From the circuit,

Req = 30/2 = 15 A ---------------(2) 

Equating (1) and (2)

12 + 10 R1 / (3 R1 +10) = 15

10 R1 / (3 R1 +10) = 3

10 R1= (9 R1 + 30)

Thus, R1 = 30 ohm. 

OR

Calculate the total resistance of the circuit and find the total current in the circuit.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_170.1

Answer- 

CBSE Class 10 Science Term 2 Sample Paper & Solutions_180.1

Question 13- Gas A, found in the upper layers of the atmosphere, is a deadly poison but is essential for all living beings. The amount of this gas started declining sharply in the 1980s. 

a) Identify Gas A. How is it formed at higher levels of the atmosphere? 

Answer- Gas A is Ozone. Alternatively, accept the formula of the gas. Ozone at the higher levels of the atmosphere is a product of UV radiation acting on oxygen (O2) molecules. The higher energy UV radiations split apart some molecular oxygen (O2) into free oxygen (O) atoms. These atoms then combine with molecular oxygen to form ozone.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_190.1

b) Why is it essential for all living beings? State the cause for the depletion of this gas.

Answer- Ozone shields the surface of the earth / protects living organisms from ultraviolet (UV) radiation released by the sun. Chlorofluorocarbons (CFCs) which are used as refrigerants / in fire extinguishers lead to depletion of the ozone layer.

Question 14- Sahil performed an experiment to study the inheritance pattern of genes. He crossed tall pea plants (TT) with short pea plants (tt) and obtained all tall plants in F1 generation.

a) What will be the set of genes present in the F1 generation? (1 Mark)

Answer- Tt

b) Give a reason why only tall plants are observed in F1 progeny. (1 Mark)

Answer- Traits like ‘T’ are called dominant traits, while those that behave like ‘t’ are called recessive traits./Alternatively accept the definition of dominant and recessive traits with examples of T and t respectively /Alternatively accept the law of Dominance with examples of T and t.

c) When F1 plants were self-pollinated, a total of 800 plants were produced. How many of these would be tall, medium height or short plants? Give the genotype of F 2 generation. (2 Marks)

Answer- Out of 800 plants 600 plants will be tall and 200 plants will be small, 1 TT: 2Tt: 1tt

OR

When F1 plants were cross-pollinated with plants having tt genes, a total of 800 plants were produced. How many of these would be tall, medium height or short plants? Give the genotype of F 2 generation. 

Answer- In the cross between Tt X tt, 400 Tall (Tt) and 400 short (tt) plants will be produced. 1Tt:1tt

Question 15- Ansari Sir was demonstrating an experiment in his class with the setup as shown in the figure below.

CBSE Class 10 Science Term 2 Sample Paper & Solutions_200.1

A magnet is attached to a spring. The magnet can go in and out of the stationary coil. He lifted the Magnet and released it to make it oscillate through the coil. Based on your understanding of the phenomenon, answer the following questions.

a) What is the principle that Ansari Sir is trying to demonstrate?

Answer- Sir is trying to demonstrate the principle of Electromagnetic induction.

b) What will be observed when the Magnet starts oscillating through the coil. Explain the reason behind this observation.

Answer- There will be induced current in the coil due to relative motion between the magnet and the coil. Changing the magnetic field around the coil generates induced current

c) Consider the situation where the Magnet goes in and out of the coil. State two changes that could be made to increase the deflection in the galvanometer. 

Answer- Using a stronger magnet, using a coil with more number of turns.

OR

Is there any difference in the observations in the galvanometer when the Magnet swings in and then out of the stationary coil? Justify your answer.

Answer- When the magnet moves into the coil, the ammeter shows a momentary deflection towards one side says left.
When the magnet moves out of the coil, the ammeter shows a momentary deflection 4 6 now towards the right.
This is due to changing magnetic field /flux associated with the coil as the magnet moves in and out.
Alternatively, the flux increases when the magnet goes in and it decreases when the magnet goes out.

CBSE Class 10 Science Term 1 Sample Paper PDF

CBSE Class 10 Science Term 1 Solution PDF

Steps to download CBSE Class 10 Science Sample Paper 2022

Download the sample paper class 10 science 2021-22 with solutions for the term-2 exam by following the below-mentioned steps :

Step I- Visit the official website of CBSE Academic @ www.cbseacademic.nic.in or Click on the CBSE Class 10 Science Sample Paper with Solutions for Term 2 Exam mentioned above. 

Step II- Click on the notification appearing in the academic section- “Sample Question Papers of Classes X for Term 2 Exams 2022”.

Step III- Now click on the link mentioned under “Sample Papers Class X”.

Step IV- The list of all subjects “Class X Sample Question Paper & Marking Scheme for Exam 2022” appears on the screen. 

Step V- Click on “SQP” for “Science” and download CBSE Class 10th Science Sample Paper 2022 Term-2 pdf along with Solution. 

Step VI- Check the marking scheme after attempting each subject CBSE Class 10th Science Sample Paper 2022 Term-2.

CBSE Class 10 Science Term 2 Answer Key 2022- Click Here

Related Links
CBSE Class 10 English Syllabus Term-2 CBSE Class 10 Science Syllabus Term-2
CBSE Class 10 Maths Syllabus Term-2 CBSE Class 10 Maths Sample Paper Term 2
CBSE Class 10 Social Science Sample Paper Term-2 CBSE Class 10 Hindi Sample Paper Term 2
CBSE Class 10 English Sample Paper Term-2 CBSE Class 10 Hindi Syllabus Term 2

CBSE Class 10 Term 2 Admit Card 2022 Out- Click to Download

CBSE Class 10 Term 2 Date Sheet 2022 Out- Click to Check

Science Class 10 Term 2 Sample Paper: FAQs

Ans. In this article, we have provided the direct links to download Class 10 Science Sample Paper 2022.

Ans. Yes, the questions asked in Class 10th Science term 2 will be of descriptive type.

Ans. A total of 15 questions will be asked in the Class 10 Science paper which is going to be held on 10th May 2022.

Important Links