The National Test Agency has conducted the CSIR UGC NET December 2025 to determine the eligibility of Indian nationals for award of JRF and appointment as Assistant Professor, appointment as Assistant Professor and admission to Ph.D., and admission to Ph.D. only in Indian universities and colleges. Now, the NTA will release the official CSIR NET December Answer Key today, i.e., on 26th December 2025, carrying all the correct answers for the questions that were asked in the computer-based test.
CSIR NET December Answer Key 2025 Out Today
The CSIR National Eligibility Test was conducted on 18th December 2025 in 2 shifts, for which the CSIR NET December Answer Key 2025 will be released by the National Test Agency at their official website www.csirnet.nta.ac.in. The answer key will be released in the PDF format, and candidates will require their login details, i.e., Application Number and Date of Birth, to download the answer key. The answer key helps candidates to evaluate their performance before the official result is announced.
CSIR NET Answer Key 2025
The Provisional CSIR NET Answer Key 2025 will be released first, and candidates will be allowed to raise objections if they find any discrepancies. To raise objections, candidates will need to log in using their application number & date of birth and pay a nominal fee per question challenged. A final answer key will be released after reviewing all the objections, and it will be used to prepare the final result.
| CSIR NET December Answer Key 2025 Highlight | |
| Conducting Body | National Testing Agency (NTA) |
| Exam Name | CSIR UGC NET December 2025 |
| Post Name | Junior Fellowship (JRF), Lectureship/Assistant Professor, and Ph.D. |
| Mode of Answer Key | Online |
| Answer Key Release Date | 26th December 2025 (Expected) |
| Raise Objections | To be notified |
| Exam Date | 18th December 2025 |
| Marking Scheme |
|
| Official Website | www.csirnet.nta.ac.in |
CSIR NET December Answer Key 2025 Link
The download link for CSIR NET Answer Key 2025 for December session will be made available today, i.e., on 26th December 2025 (expected), by the National Test Agency at their official website www.csirnet.nta.ac.in. The answer key helps candidates to evaluate their performance before the official result is announced, as it provides correct answers to all questions. To download the answer key, we will also provide a direct link below once it is officially released.
Steps to download the CSIR NET Answer Key 2025
Candidates can download their answer key from the CSIR NET official website at www.csirnet.nta.nic.in by following the step-by-step process.
- Visit the official website of the National Testing Agency (NTA) at www.csirnet.nta.nic.in.
- On the homepage, look for the “Latest News” section.
- Candidates find a link to download the “Joint CSIR NET December 2025 – Click Here to Answer Key Challenge.” Click on that link.
- Candidates are redirected to a new page. Here, candidates need to log in by entering their application number and date of birth.
- Enter the Security Pin as shown in the image and click on the Submit tab.
- After successfully logging in, the answer key appears on the screen.
- Download the answer key and calculate your estimated score.
UGC NET December Answer Key 2025 Marking Scheme
The CSIR NET exam has a marking scheme where each correct answer in Part A and Part B is awarded 2 marks, while in Part C, correct answers are awarded 4 marks. There is negative marking for incorrect answers in all parts, with a deduction of 25% of the allotted marks for each wrong answer. This means a deduction of 0.5 marks for incorrect answers in Part A and B, and a deduction of 1 mark for incorrect answers in Part C.
- Correct Answer: (i) Each correct answer in Part A and Part B is awarded 2 marks
(ii) Each correct answer in Part C is awarded 4 Marks - Incorrect Answer: (i) Deduction of 0.5 marks for incorrect answers in Part A and B
(ii) Deduction of 1 mark for incorrect answers in Part C.
CSIR NET Answer Key December 2025: Raise Objection
The National Testing Agency (NTA) will also provide a facility to raise objection to the candidates if they are not satisfied with the Answer Key. Candidates can raise objections and submit a challenge to the CSIR NET December Answer Key 2025 within a given time frame, along with the non-refundable processing challenge fee of Rs. 200/- per question. The processing fee will be paid online through Debit/Credit Card/Net Banking, and the challenge without receipt of the processing fee will not be accepted.
Steps to Raise Objections to CSIR NET December Answer Key 2025
- Go to the official website National Testing Agency (NTA) at https://csirnet.nta.ac.in.
- Click on the link that reads “Joint CSIR UGC NET Answer Key Challenge Open Click Here”
- A new login page appears on the screen. Enter your Application Number and Date of Birth enter your Security PIN as displayed then click on submit button.
- Click on “View Question Paper” for marked responses and to view or challenge the Answer keys, click on the link “Click to view /Challenge Answer Key”.
- You will see Question IDs in sequential order.
- The ID next to the question under the column ‘Correct Option(s)’ stands for the correct Answer Key to be used by NTA.
- If candidates want to challenge this option, they may use any one or more of the Option IDs given in the next four columns by clicking the check box.
- After clicking your desired option, scroll down, ‘Save your Claims’ and move to next screen.
- You will see a display of all the Option IDs you have challenged.
- You may want to upload supporting documents in which you can select ‘Choose File’ and upload (all documents are to be put in a single PDF file only).
- Click on ‘Save your Claims and pay fee’ or in case to modify the claims, click on ‘Modify your Claims’.
- After saving the claims, you will find a screen displaying your challenges.
- Kindly pay the fee by clicking on ‘Pay Fee’. The claims will be saved finally after successful payment of a required fee.
- Select Mode of Payment and Pay a non-refundable processing fee of Rs. 200/- for each question challenged.


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